48x^2+77x^2-35x=0

Solution for 48x^2+77x^2-35x=0 equation:

48x^2+77x^2-35x=0

We add all the numbers together, and all the variables

125x^2-35x=0

a = 125; b = -35; c = 0;
Δ = b2-4ac
Δ = -352-4·125·0
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1225}=35$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-35}{2*125}=\frac{0}{250}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+35}{2*125}=\frac{70}{250}
=7/25
$